Caz 1:b=0⇒Uc(2a+2b)=Uc(2a+1)
a01,5,92,63,74,8Uc(2a+1)23597nr.a13222suma Uc2⋅1=23⋅3=95⋅2=109⋅2=187⋅2=14 Total: 2+9+10+18+14=53
Caz 2:b=1..9⇒Uc(2a+2b)=Uc(2a+5)
a01,5,92,63,74,8Uc(2a+5)67931nr.a13222suma Uc6⋅1=67⋅3=219⋅2=183⋅2=61⋅2=2 Avem 9 variante pt. b, deci:
Total: 9⋅(6+21+18+6+2)=477
Răspuns: 53+477=530.