E.370. Aflați numărul natural xxx din egalitatea: 342−32+{20180+23+71⋅[53−22⋅(103+32):x]}=2017⋅2018−20172.34^2-3^2+\{2018^0+2^3+7^1 \cdot [5^3-2^2 \cdot (10^3+3^2):x]\} = 2017 \cdot 2018 - 2017^2.342−32+{20180+23+71⋅[53−22⋅(103+32):x]}=2017⋅2018−20172.
Răspuns: x=2018.x=2018.x=2018.