E.468. Calculați abc‾−bca‾−cab‾\overline{abc} - \overline{bca} - \overline{cab}abc−bca−cab știind că a=5⋅7−[40:8+3⋅(42+14):8], 15+b=27−ba=5 \cdot 7 - [40:8 + 3 \cdot (42+14):8],~15+b=27-ba=5⋅7−[40:8+3⋅(42+14):8], 15+b=27−b și 3c=b.3c=b.3c=b.
Răspuns: 37.37.37.
a=35−(5+3⋅56:8)=35−26⇒a=9.a=35 - (5 + 3 \cdot 56:8)=35-26 \Rightarrow \boxed{a=9}.a=35−(5+3⋅56:8)=35−26⇒a=9. 15+b=27−b⇒2b=27−15⇒b=6.15+b=27-b \Rightarrow 2b = 27-15 \Rightarrow \boxed{b=6}.15+b=27−b⇒2b=27−15⇒b=6. 3c=6⇒c=2.3c=6 \Rightarrow \boxed{c=2}.3c=6⇒c=2.
abc‾−bca‾−cab‾=962−629−296=37.\overline{abc} - \overline{bca} - \overline{cab} = 962-629-296 =37.abc−bca−cab=962−629−296=37.